The winning Texas Pick 3 numbers for November 12, 2003 were: day 6-0-2; night 7-9-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 12, 2003 | Night | 7-9-5 | 21 | 3 |
| Nov 12, 2003 | Day | 6-0-2 | 8 | 8 |
| Nov 11, 2003 | Night | 7-4-3 | 14 | 5 |
| Nov 11, 2003 | Day | 9-2-6 | 17 | 8 |
| Nov 10, 2003 | Night | 5-3-9 | 17 | 8 |
| Nov 10, 2003 | Day | 9-7-8 | 24 | 6 |
| Nov 8, 2003 | Night | 3-9-1 | 13 | 4 |
| Nov 8, 2003 | Day | 9-8-4 | 21 | 3 |
| Nov 7, 2003 | Night | 8-9-7 | 24 | 6 |
| Nov 7, 2003 | Day | 2-2-2 | 6 | 6 |
| Nov 6, 2003 | Night | 9-6-7 | 22 | 4 |
| Nov 6, 2003 | Day | 3-9-2 | 14 | 5 |