The winning Texas Pick 3 numbers for November 4, 2003 were: day 3-8-9; night 9-8-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 4, 2003 | Night | 9-8-6 | 23 | 5 |
| Nov 4, 2003 | Day | 3-8-9 | 20 | 2 |
| Nov 3, 2003 | Night | 0-2-8 | 10 | 1 |
| Nov 3, 2003 | Day | 1-1-0 | 2 | 2 |
| Nov 1, 2003 | Night | 3-5-5 | 13 | 4 |
| Nov 1, 2003 | Day | 3-4-8 | 15 | 6 |
| Oct 31, 2003 | Night | 1-5-5 | 11 | 2 |
| Oct 31, 2003 | Day | 3-4-8 | 15 | 6 |
| Oct 30, 2003 | Night | 0-6-0 | 6 | 6 |
| Oct 30, 2003 | Day | 9-6-7 | 22 | 4 |
| Oct 29, 2003 | Night | 9-6-7 | 22 | 4 |
| Oct 29, 2003 | Day | 6-1-3 | 10 | 1 |