The winning Texas Pick 3 numbers for September 10, 2003 were: day 1-9-3; night 2-9-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 10, 2003 | Night | 2-9-9 | 20 | 2 |
| Sep 10, 2003 | Day | 1-9-3 | 13 | 4 |
| Sep 9, 2003 | Night | 8-5-0 | 13 | 4 |
| Sep 9, 2003 | Day | 1-1-4 | 6 | 6 |
| Sep 8, 2003 | Night | 4-4-3 | 11 | 2 |
| Sep 8, 2003 | Day | 7-6-9 | 22 | 4 |
| Sep 6, 2003 | Night | 5-8-5 | 18 | 9 |
| Sep 6, 2003 | Day | 4-0-2 | 6 | 6 |
| Sep 5, 2003 | Night | 1-1-9 | 11 | 2 |
| Sep 5, 2003 | Day | 9-7-0 | 16 | 7 |
| Sep 4, 2003 | Night | 5-0-1 | 6 | 6 |
| Sep 4, 2003 | Day | 6-4-0 | 10 | 1 |