The winning Texas Pick 3 numbers for August 4, 2003 were: day 2-1-6; night 5-4-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 4, 2003 | Night | 5-4-9 | 18 | 9 |
| Aug 4, 2003 | Day | 2-1-6 | 9 | 9 |
| Aug 2, 2003 | Night | 1-6-5 | 12 | 3 |
| Aug 2, 2003 | Day | 2-5-9 | 16 | 7 |
| Aug 1, 2003 | Night | 3-2-5 | 10 | 1 |
| Aug 1, 2003 | Day | 8-5-1 | 14 | 5 |
| Jul 31, 2003 | Night | 0-4-3 | 7 | 7 |
| Jul 31, 2003 | Day | 1-7-1 | 9 | 9 |
| Jul 30, 2003 | Night | 3-9-6 | 18 | 9 |
| Jul 30, 2003 | Day | 2-7-7 | 16 | 7 |
| Jul 29, 2003 | Night | 6-5-3 | 14 | 5 |
| Jul 29, 2003 | Day | 0-6-2 | 8 | 8 |