The winning Texas Pick 3 numbers for December 17, 2002 were: day 7-7-9; night 0-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 17, 2002 | Night | 0-7-0 | 7 | 7 |
| Dec 17, 2002 | Day | 7-7-9 | 23 | 5 |
| Dec 16, 2002 | Night | 4-7-3 | 14 | 5 |
| Dec 16, 2002 | Day | 2-0-5 | 7 | 7 |
| Dec 14, 2002 | Night | 0-4-6 | 10 | 1 |
| Dec 14, 2002 | Day | 5-8-5 | 18 | 9 |
| Dec 13, 2002 | Night | 5-9-4 | 18 | 9 |
| Dec 13, 2002 | Day | 0-9-5 | 14 | 5 |
| Dec 12, 2002 | Night | 9-0-5 | 14 | 5 |
| Dec 12, 2002 | Day | 1-0-0 | 1 | 1 |
| Dec 11, 2002 | Night | 0-8-0 | 8 | 8 |
| Dec 11, 2002 | Day | 0-2-0 | 2 | 2 |