The winning Texas Pick 3 numbers for December 5, 2002 were: day 8-0-6; night 3-7-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 5, 2002 | Night | 3-7-2 | 12 | 3 |
| Dec 5, 2002 | Day | 8-0-6 | 14 | 5 |
| Dec 4, 2002 | Night | 2-0-3 | 5 | 5 |
| Dec 4, 2002 | Day | 3-3-5 | 11 | 2 |
| Dec 3, 2002 | Night | 5-9-5 | 19 | 1 |
| Dec 3, 2002 | Day | 1-3-8 | 12 | 3 |
| Dec 2, 2002 | Night | 5-1-5 | 11 | 2 |
| Dec 2, 2002 | Day | 1-3-2 | 6 | 6 |
| Nov 30, 2002 | Night | 2-3-1 | 6 | 6 |
| Nov 30, 2002 | Day | 9-8-5 | 22 | 4 |
| Nov 29, 2002 | Night | 4-1-0 | 5 | 5 |
| Nov 29, 2002 | Day | 0-1-2 | 3 | 3 |