The winning Texas Pick 3 numbers for November 6, 2002 were: day 7-2-0; night 9-3-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 6, 2002 | Night | 9-3-0 | 12 | 3 |
| Nov 6, 2002 | Day | 7-2-0 | 9 | 9 |
| Nov 5, 2002 | Night | 7-0-7 | 14 | 5 |
| Nov 5, 2002 | Day | 5-2-7 | 14 | 5 |
| Nov 4, 2002 | Night | 7-1-9 | 17 | 8 |
| Nov 4, 2002 | Day | 2-5-4 | 11 | 2 |
| Nov 2, 2002 | Night | 4-6-7 | 17 | 8 |
| Nov 2, 2002 | Day | 7-4-4 | 15 | 6 |
| Nov 1, 2002 | Night | 4-9-8 | 21 | 3 |
| Nov 1, 2002 | Day | 8-6-0 | 14 | 5 |
| Oct 31, 2002 | Night | 9-6-8 | 23 | 5 |
| Oct 31, 2002 | Day | 1-0-0 | 1 | 1 |