The winning Texas Pick 3 numbers for August 17, 2002 were: day 7-4-7; night 7-0-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 17, 2002 | Night | 7-0-3 | 10 | 1 |
| Aug 17, 2002 | Day | 7-4-7 | 18 | 9 |
| Aug 16, 2002 | Night | 6-9-6 | 21 | 3 |
| Aug 16, 2002 | Day | 9-3-3 | 15 | 6 |
| Aug 15, 2002 | Night | 4-6-9 | 19 | 1 |
| Aug 15, 2002 | Day | 7-4-3 | 14 | 5 |
| Aug 14, 2002 | Night | 4-7-3 | 14 | 5 |
| Aug 14, 2002 | Day | 6-5-0 | 11 | 2 |
| Aug 13, 2002 | Night | 2-7-2 | 11 | 2 |
| Aug 13, 2002 | Day | 2-2-2 | 6 | 6 |
| Aug 12, 2002 | Night | 0-6-8 | 14 | 5 |
| Aug 12, 2002 | Day | 3-0-8 | 11 | 2 |