The winning Texas Pick 3 numbers for August 5, 2002 were: day 6-4-2; night 2-5-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 5, 2002 | Night | 2-5-9 | 16 | 7 |
| Aug 5, 2002 | Day | 6-4-2 | 12 | 3 |
| Aug 3, 2002 | Night | 7-2-0 | 9 | 9 |
| Aug 3, 2002 | Day | 8-6-3 | 17 | 8 |
| Aug 2, 2002 | Night | 6-9-4 | 19 | 1 |
| Aug 2, 2002 | Day | 1-2-6 | 9 | 9 |
| Aug 1, 2002 | Night | 6-4-5 | 15 | 6 |
| Aug 1, 2002 | Day | 8-4-8 | 20 | 2 |
| Jul 31, 2002 | Night | 8-5-0 | 13 | 4 |
| Jul 31, 2002 | Day | 8-3-6 | 17 | 8 |
| Jul 30, 2002 | Night | 6-0-1 | 7 | 7 |
| Jul 30, 2002 | Day | 9-1-0 | 10 | 1 |