The winning Texas Pick 3 numbers for December 2, 1999 were: night 4-4-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 2, 1999 | Night | 4-4-7 | 15 | 6 |
| Dec 1, 1999 | Night | 0-7-0 | 7 | 7 |
| Nov 30, 1999 | Night | 5-4-9 | 18 | 9 |
| Nov 29, 1999 | Night | 5-9-1 | 15 | 6 |
| Nov 27, 1999 | Night | 2-0-1 | 3 | 3 |
| Nov 26, 1999 | Night | 3-6-0 | 9 | 9 |