The winning Texas Pick 3 numbers for November 27, 1999 were: night 2-0-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 27, 1999 | Night | 2-0-1 | 3 | 3 |
| Nov 26, 1999 | Night | 3-6-0 | 9 | 9 |
| Nov 25, 1999 | Night | 0-8-3 | 11 | 2 |
| Nov 24, 1999 | Night | 9-6-3 | 18 | 9 |
| Nov 23, 1999 | Night | 5-7-0 | 12 | 3 |
| Nov 22, 1999 | Night | 0-4-4 | 8 | 8 |