The winning Texas Pick 3 numbers for November 2, 1999 were: night 1-6-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 2, 1999 | Night | 1-6-7 | 14 | 5 |
| Nov 1, 1999 | Night | 9-1-5 | 15 | 6 |
| Oct 30, 1999 | Night | 5-3-7 | 15 | 6 |
| Oct 29, 1999 | Night | 4-3-3 | 10 | 1 |
| Oct 28, 1999 | Night | 0-8-4 | 12 | 3 |
| Oct 27, 1999 | Night | 4-8-5 | 17 | 8 |