The winning Texas Pick 3 numbers for October 27, 1999 were: night 4-8-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 27, 1999 | Night | 4-8-5 | 17 | 8 |
| Oct 26, 1999 | Night | 2-5-1 | 8 | 8 |
| Oct 25, 1999 | Night | 0-7-8 | 15 | 6 |
| Oct 23, 1999 | Night | 8-8-8 | 24 | 6 |
| Oct 22, 1999 | Night | 9-2-3 | 14 | 5 |
| Oct 21, 1999 | Night | 5-9-9 | 23 | 5 |