The winning Texas Pick 3 numbers for October 8, 1999 were: night 4-8-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 8, 1999 | Night | 4-8-5 | 17 | 8 |
| Oct 7, 1999 | Night | 1-9-0 | 10 | 1 |
| Oct 6, 1999 | Night | 1-6-3 | 10 | 1 |
| Oct 5, 1999 | Night | 6-4-8 | 18 | 9 |
| Oct 4, 1999 | Night | 1-0-5 | 6 | 6 |
| Oct 2, 1999 | Night | 1-5-4 | 10 | 1 |