The winning Texas Pick 3 numbers for October 2, 1999 were: night 1-5-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 2, 1999 | Night | 1-5-4 | 10 | 1 |
| Oct 1, 1999 | Night | 8-4-9 | 21 | 3 |
| Sep 30, 1999 | Night | 1-7-6 | 14 | 5 |
| Sep 29, 1999 | Night | 2-3-5 | 10 | 1 |
| Sep 28, 1999 | Night | 1-6-3 | 10 | 1 |
| Sep 27, 1999 | Night | 8-5-1 | 14 | 5 |