The winning Texas Pick 3 numbers for September 25, 1999 were: night 8-1-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 25, 1999 | Night | 8-1-0 | 9 | 9 |
| Sep 24, 1999 | Night | 1-5-0 | 6 | 6 |
| Sep 23, 1999 | Night | 8-5-9 | 22 | 4 |
| Sep 22, 1999 | Night | 1-6-9 | 16 | 7 |
| Sep 21, 1999 | Night | 0-3-2 | 5 | 5 |
| Sep 20, 1999 | Night | 0-9-6 | 15 | 6 |