The winning Texas Pick 3 numbers for September 21, 1999 were: night 0-3-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 21, 1999 | Night | 0-3-2 | 5 | 5 |
| Sep 20, 1999 | Night | 0-9-6 | 15 | 6 |
| Sep 18, 1999 | Night | 0-9-4 | 13 | 4 |
| Sep 17, 1999 | Night | 7-4-4 | 15 | 6 |
| Sep 16, 1999 | Night | 8-5-0 | 13 | 4 |
| Sep 15, 1999 | Night | 0-6-4 | 10 | 1 |