The winning Texas Pick 3 numbers for September 10, 1999 were: night 8-1-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 10, 1999 | Night | 8-1-5 | 14 | 5 |
| Sep 9, 1999 | Night | 6-0-0 | 6 | 6 |
| Sep 8, 1999 | Night | 0-2-0 | 2 | 2 |
| Sep 7, 1999 | Night | 8-0-6 | 14 | 5 |
| Sep 6, 1999 | Night | 6-6-2 | 14 | 5 |
| Sep 4, 1999 | Night | 9-0-3 | 12 | 3 |