The winning Texas Pick 3 numbers for August 26, 1999 were: night 3-7-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 26, 1999 | Night | 3-7-8 | 18 | 9 |
| Aug 25, 1999 | Night | 4-2-5 | 11 | 2 |
| Aug 24, 1999 | Night | 0-8-5 | 13 | 4 |
| Aug 23, 1999 | Night | 6-4-2 | 12 | 3 |
| Aug 21, 1999 | Night | 4-5-4 | 13 | 4 |
| Aug 20, 1999 | Night | 8-9-1 | 18 | 9 |