The winning Texas Pick 3 numbers for August 14, 1999 were: night 1-3-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 14, 1999 | Night | 1-3-0 | 4 | 4 |
| Aug 13, 1999 | Night | 7-1-5 | 13 | 4 |
| Aug 12, 1999 | Night | 9-0-6 | 15 | 6 |
| Aug 11, 1999 | Night | 3-1-8 | 12 | 3 |
| Aug 10, 1999 | Night | 5-6-3 | 14 | 5 |
| Aug 9, 1999 | Night | 5-9-1 | 15 | 6 |