The winning Texas Pick 3 numbers for August 11, 1999 were: night 3-1-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 11, 1999 | Night | 3-1-8 | 12 | 3 |
| Aug 10, 1999 | Night | 5-6-3 | 14 | 5 |
| Aug 9, 1999 | Night | 5-9-1 | 15 | 6 |
| Aug 7, 1999 | Night | 8-0-1 | 9 | 9 |
| Aug 6, 1999 | Night | 7-7-0 | 14 | 5 |
| Aug 5, 1999 | Night | 7-8-1 | 16 | 7 |