The winning Texas Pick 3 numbers for June 12, 1999 were: night 0-3-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jun 12, 1999 | Night | 0-3-9 | 12 | 3 |
| Jun 11, 1999 | Night | 6-7-6 | 19 | 1 |
| Jun 10, 1999 | Night | 5-3-4 | 12 | 3 |
| Jun 9, 1999 | Night | 9-5-3 | 17 | 8 |
| Jun 8, 1999 | Night | 0-0-4 | 4 | 4 |
| Jun 7, 1999 | Night | 6-0-3 | 9 | 9 |