The winning Texas Pick 3 numbers for December 22, 1998 were: night 6-9-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 22, 1998 | Night | 6-9-1 | 16 | 7 |
| Dec 21, 1998 | Night | 8-6-3 | 17 | 8 |
| Dec 19, 1998 | Night | 6-1-8 | 15 | 6 |
| Dec 18, 1998 | Night | 2-5-3 | 10 | 1 |
| Dec 17, 1998 | Night | 0-4-6 | 10 | 1 |
| Dec 16, 1998 | Night | 0-4-8 | 12 | 3 |