The winning Texas Pick 3 numbers for December 12, 1998 were: night 6-7-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 12, 1998 | Night | 6-7-6 | 19 | 1 |
| Dec 11, 1998 | Night | 6-3-2 | 11 | 2 |
| Dec 10, 1998 | Night | 6-8-8 | 22 | 4 |
| Dec 9, 1998 | Night | 4-3-8 | 15 | 6 |
| Dec 8, 1998 | Night | 0-1-2 | 3 | 3 |
| Dec 7, 1998 | Night | 8-6-7 | 21 | 3 |