The winning Texas Pick 3 numbers for November 16, 1998 were: night 4-2-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 16, 1998 | Night | 4-2-9 | 15 | 6 |
| Nov 14, 1998 | Night | 3-9-1 | 13 | 4 |
| Nov 13, 1998 | Night | 7-0-2 | 9 | 9 |
| Nov 12, 1998 | Night | 4-1-3 | 8 | 8 |
| Nov 11, 1998 | Night | 3-3-7 | 13 | 4 |
| Nov 10, 1998 | Night | 1-1-9 | 11 | 2 |