The winning Texas Pick 3 numbers for November 9, 1998 were: night 5-5-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 9, 1998 | Night | 5-5-8 | 18 | 9 |
| Nov 7, 1998 | Night | 1-3-2 | 6 | 6 |
| Nov 6, 1998 | Night | 3-9-2 | 14 | 5 |
| Nov 5, 1998 | Night | 2-9-8 | 19 | 1 |
| Nov 4, 1998 | Night | 8-3-9 | 20 | 2 |
| Nov 3, 1998 | Night | 8-7-7 | 22 | 4 |