The winning Texas Pick 3 numbers for October 16, 1998 were: night 8-9-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 16, 1998 | Night | 8-9-5 | 22 | 4 |
| Oct 15, 1998 | Night | 7-5-6 | 18 | 9 |
| Oct 14, 1998 | Night | 3-0-0 | 3 | 3 |
| Oct 13, 1998 | Night | 4-0-2 | 6 | 6 |
| Oct 12, 1998 | Night | 0-0-3 | 3 | 3 |
| Oct 10, 1998 | Night | 0-4-9 | 13 | 4 |