The winning Texas Pick 3 numbers for October 9, 1998 were: night 6-7-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 9, 1998 | Night | 6-7-4 | 17 | 8 |
| Oct 8, 1998 | Night | 7-3-6 | 16 | 7 |
| Oct 7, 1998 | Night | 7-6-1 | 14 | 5 |
| Oct 6, 1998 | Night | 3-3-6 | 12 | 3 |
| Oct 5, 1998 | Night | 8-7-3 | 18 | 9 |
| Oct 3, 1998 | Night | 1-4-3 | 8 | 8 |