The winning Texas Pick 3 numbers for September 19, 1998 were: night 5-9-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 19, 1998 | Night | 5-9-9 | 23 | 5 |
| Sep 18, 1998 | Night | 6-4-0 | 10 | 1 |
| Sep 17, 1998 | Night | 5-9-9 | 23 | 5 |
| Sep 16, 1998 | Night | 6-4-9 | 19 | 1 |
| Sep 15, 1998 | Night | 1-9-3 | 13 | 4 |
| Sep 14, 1998 | Night | 8-4-4 | 16 | 7 |