The winning Texas Pick 3 numbers for September 11, 1998 were: night 4-5-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 11, 1998 | Night | 4-5-8 | 17 | 8 |
| Sep 10, 1998 | Night | 1-6-5 | 12 | 3 |
| Sep 9, 1998 | Night | 2-9-0 | 11 | 2 |
| Sep 8, 1998 | Night | 4-4-1 | 9 | 9 |
| Sep 7, 1998 | Night | 9-7-2 | 18 | 9 |
| Sep 5, 1998 | Night | 8-7-8 | 23 | 5 |