The winning Texas Pick 3 numbers for August 14, 1998 were: night 8-2-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 14, 1998 | Night | 8-2-2 | 12 | 3 |
| Aug 13, 1998 | Night | 7-0-4 | 11 | 2 |
| Aug 12, 1998 | Night | 5-9-0 | 14 | 5 |
| Aug 11, 1998 | Night | 5-6-8 | 19 | 1 |
| Aug 10, 1998 | Night | 8-7-6 | 21 | 3 |
| Aug 8, 1998 | Night | 0-7-9 | 16 | 7 |