The winning Texas Pick 3 numbers for August 6, 1998 were: night 3-0-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 6, 1998 | Night | 3-0-0 | 3 | 3 |
| Aug 5, 1998 | Night | 5-1-8 | 14 | 5 |
| Aug 4, 1998 | Night | 2-5-0 | 7 | 7 |
| Aug 3, 1998 | Night | 9-9-1 | 19 | 1 |
| Aug 1, 1998 | Night | 0-4-1 | 5 | 5 |
| Jul 31, 1998 | Night | 4-2-0 | 6 | 6 |