The winning Texas Pick 3 numbers for June 12, 1998 were: night 9-9-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jun 12, 1998 | Night | 9-9-7 | 25 | 7 |
| Jun 11, 1998 | Night | 6-4-4 | 14 | 5 |
| Jun 10, 1998 | Night | 7-1-9 | 17 | 8 |
| Jun 9, 1998 | Night | 8-1-0 | 9 | 9 |
| Jun 8, 1998 | Night | 5-4-6 | 15 | 6 |
| Jun 6, 1998 | Night | 0-5-2 | 7 | 7 |