The winning Texas Pick 3 numbers for August 4, 1997 were: night 3-3-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 4, 1997 | Night | 3-3-0 | 6 | 6 |
| Aug 2, 1997 | Night | 0-2-5 | 7 | 7 |
| Aug 1, 1997 | Night | 4-4-4 | 12 | 3 |
| Jul 31, 1997 | Night | 7-6-1 | 14 | 5 |
| Jul 30, 1997 | Night | 0-1-7 | 8 | 8 |
| Jul 29, 1997 | Night | 5-5-6 | 16 | 7 |