The winning Texas Pick 3 numbers for December 21, 1996 were: night 9-8-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 21, 1996 | Night | 9-8-3 | 20 | 2 |
| Dec 20, 1996 | Night | 8-0-1 | 9 | 9 |
| Dec 19, 1996 | Night | 9-7-7 | 23 | 5 |
| Dec 18, 1996 | Night | 3-1-8 | 12 | 3 |
| Dec 17, 1996 | Night | 9-5-5 | 19 | 1 |
| Dec 16, 1996 | Night | 5-8-9 | 22 | 4 |