The winning Texas Pick 3 numbers for September 26, 1996 were: night 8-3-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 26, 1996 | Night | 8-3-9 | 20 | 2 |
| Sep 25, 1996 | Night | 2-5-3 | 10 | 1 |
| Sep 24, 1996 | Night | 8-9-0 | 17 | 8 |
| Sep 23, 1996 | Night | 2-7-9 | 18 | 9 |
| Sep 21, 1996 | Night | 2-2-2 | 6 | 6 |
| Sep 20, 1996 | Night | 5-7-3 | 15 | 6 |