The winning Texas Pick 3 numbers for September 4, 1996 were: night 0-2-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 4, 1996 | Night | 0-2-2 | 4 | 4 |
| Sep 3, 1996 | Night | 2-7-6 | 15 | 6 |
| Sep 2, 1996 | Night | 0-0-5 | 5 | 5 |
| Aug 31, 1996 | Night | 7-1-3 | 11 | 2 |
| Aug 30, 1996 | Night | 8-2-9 | 19 | 1 |
| Aug 29, 1996 | Night | 5-5-0 | 10 | 1 |