The winning Texas Pick 3 numbers for August 27, 1996 were: night 6-8-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 27, 1996 | Night | 6-8-4 | 18 | 9 |
| Aug 26, 1996 | Night | 8-4-9 | 21 | 3 |
| Aug 24, 1996 | Night | 0-3-1 | 4 | 4 |
| Aug 23, 1996 | Night | 8-6-2 | 16 | 7 |
| Aug 22, 1996 | Night | 7-7-5 | 19 | 1 |
| Aug 21, 1996 | Night | 2-7-5 | 14 | 5 |