The winning Texas Pick 3 numbers for August 21, 1996 were: night 2-7-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 21, 1996 | Night | 2-7-5 | 14 | 5 |
| Aug 20, 1996 | Night | 0-5-7 | 12 | 3 |
| Aug 19, 1996 | Night | 8-4-5 | 17 | 8 |
| Aug 17, 1996 | Night | 7-3-5 | 15 | 6 |
| Aug 16, 1996 | Night | 1-4-2 | 7 | 7 |
| Aug 15, 1996 | Night | 7-2-1 | 10 | 1 |