The winning Texas Pick 3 numbers for August 13, 1996 were: night 0-5-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 13, 1996 | Night | 0-5-1 | 6 | 6 |
| Aug 12, 1996 | Night | 5-5-8 | 18 | 9 |
| Aug 10, 1996 | Night | 6-2-9 | 17 | 8 |
| Aug 9, 1996 | Night | 7-0-9 | 16 | 7 |
| Aug 8, 1996 | Night | 3-6-0 | 9 | 9 |
| Aug 7, 1996 | Night | 6-2-1 | 9 | 9 |