The winning Texas Pick 3 numbers for August 2, 1996 were: night 4-2-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 2, 1996 | Night | 4-2-5 | 11 | 2 |
| Aug 1, 1996 | Night | 0-1-3 | 4 | 4 |
| Jul 31, 1996 | Night | 9-2-8 | 19 | 1 |
| Jul 30, 1996 | Night | 3-5-6 | 14 | 5 |
| Jul 29, 1996 | Night | 9-8-1 | 18 | 9 |
| Jul 27, 1996 | Night | 0-4-1 | 5 | 5 |