The winning Texas Pick 3 numbers for March 16, 1996 were: night 8-4-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 16, 1996 | Night | 8-4-2 | 14 | 5 |
| Mar 15, 1996 | Night | 2-9-4 | 15 | 6 |
| Mar 14, 1996 | Night | 3-0-1 | 4 | 4 |
| Mar 13, 1996 | Night | 6-1-7 | 14 | 5 |
| Mar 12, 1996 | Night | 3-9-3 | 15 | 6 |
| Mar 11, 1996 | Night | 7-0-4 | 11 | 2 |