The winning Texas Pick 3 numbers for March 4, 1996 were: night 4-8-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 4, 1996 | Night | 4-8-7 | 19 | 1 |
| Mar 2, 1996 | Night | 6-4-6 | 16 | 7 |
| Mar 1, 1996 | Night | 2-0-3 | 5 | 5 |
| Feb 29, 1996 | Night | 1-0-3 | 4 | 4 |
| Feb 28, 1996 | Night | 0-3-1 | 4 | 4 |
| Feb 27, 1996 | Night | 1-2-6 | 9 | 9 |