The winning Texas Pick 3 numbers for February 22, 1996 were: night 3-9-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Feb 22, 1996 | Night | 3-9-0 | 12 | 3 |
| Feb 21, 1996 | Night | 9-7-9 | 25 | 7 |
| Feb 20, 1996 | Night | 5-9-4 | 18 | 9 |
| Feb 19, 1996 | Night | 6-5-9 | 20 | 2 |
| Feb 17, 1996 | Night | 9-9-0 | 18 | 9 |
| Feb 16, 1996 | Night | 7-8-5 | 20 | 2 |