The winning Texas Pick 3 numbers for February 14, 1996 were: night 2-7-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Feb 14, 1996 | Night | 2-7-4 | 13 | 4 |
| Feb 13, 1996 | Night | 1-6-7 | 14 | 5 |
| Feb 12, 1996 | Night | 6-3-7 | 16 | 7 |
| Feb 10, 1996 | Night | 0-9-9 | 18 | 9 |
| Feb 9, 1996 | Night | 5-4-8 | 17 | 8 |
| Feb 8, 1996 | Night | 0-5-2 | 7 | 7 |