The winning Texas Pick 3 numbers for January 17, 1996 were: night 5-9-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jan 17, 1996 | Night | 5-9-5 | 19 | 1 |
| Jan 16, 1996 | Night | 6-7-8 | 21 | 3 |
| Jan 15, 1996 | Night | 1-8-1 | 10 | 1 |
| Jan 13, 1996 | Night | 4-6-6 | 16 | 7 |
| Jan 12, 1996 | Night | 6-1-3 | 10 | 1 |
| Jan 11, 1996 | Night | 7-6-8 | 21 | 3 |