The winning Texas Pick 3 numbers for January 4, 1996 were: night 9-9-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jan 4, 1996 | Night | 9-9-8 | 26 | 8 |
| Jan 3, 1996 | Night | 4-2-7 | 13 | 4 |
| Jan 2, 1996 | Night | 8-4-9 | 21 | 3 |
| Jan 1, 1996 | Night | 8-2-9 | 19 | 1 |
| Dec 30, 1995 | Night | 7-0-4 | 11 | 2 |
| Dec 29, 1995 | Night | 2-3-0 | 5 | 5 |