The winning Texas Pick 3 numbers for December 2, 1993 were: night 1-9-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 2, 1993 | Night | 1-9-9 | 19 | 1 |
| Dec 1, 1993 | Night | 4-1-5 | 10 | 1 |
| Nov 30, 1993 | Night | 2-4-2 | 8 | 8 |
| Nov 29, 1993 | Night | 6-9-0 | 15 | 6 |
| Nov 27, 1993 | Night | 9-5-2 | 16 | 7 |
| Nov 26, 1993 | Night | 4-2-8 | 14 | 5 |