The winning Texas Pick 3 numbers for November 16, 1993 were: night 4-3-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 16, 1993 | Night | 4-3-5 | 12 | 3 |
| Nov 15, 1993 | Night | 4-0-1 | 5 | 5 |
| Nov 13, 1993 | Night | 7-8-1 | 16 | 7 |
| Nov 12, 1993 | Night | 5-9-0 | 14 | 5 |
| Nov 11, 1993 | Night | 8-1-4 | 13 | 4 |
| Nov 10, 1993 | Night | 4-9-0 | 13 | 4 |