The winning New York Win 4 numbers for December 28, 2003 were: midday 7-7-6-5; evening 1-5-0-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 28, 2003 | Evening | 1-5-0-4 | 10 | 1 |
| Dec 28, 2003 | Midday | 7-7-6-5 | 25 | 7 |
| Dec 27, 2003 | Evening | 8-8-6-6 | 28 | 1 |
| Dec 27, 2003 | Midday | 1-7-6-6 | 20 | 2 |
| Dec 26, 2003 | Evening | 3-0-8-8 | 19 | 1 |
| Dec 26, 2003 | Midday | 6-8-7-5 | 26 | 8 |
| Dec 24, 2003 | Evening | 6-5-7-8 | 26 | 8 |
| Dec 24, 2003 | Midday | 6-5-5-4 | 20 | 2 |
| Dec 23, 2003 | Evening | 3-3-3-1 | 10 | 1 |
| Dec 23, 2003 | Midday | 5-3-2-3 | 13 | 4 |
| Dec 22, 2003 | Evening | 2-0-2-5 | 9 | 9 |
| Dec 22, 2003 | Midday | 0-0-0-7 | 7 | 7 |